2.294157
8.7178
years
11.2822
years
9
light-years
3.923
light-years
2.294157
8.7178
years
11.2822
years
9
light-years
3.923
light-years
The Twin Paradox Calculator computes the time experienced by a traveling twin versus a twin who stays on Earth, illustrating one of the most famous thought experiments in special relativity. If one twin makes a round trip at relativistic speed $$v$$, the traveling twin ages less than the stay-at-home twin by the Lorentz factor:
$$t_{\text{traveler}} = \frac{t_{\text{Earth}}}{\gamma} = t_{\text{Earth}}\sqrt{1 - \frac{v^2}{c^2}}$$
This is not a paradox in the logical sense — it has a clear resolution. The asymmetry arises because the traveling twin must accelerate and decelerate (changing inertial frames), while the Earth twin remains in a single inertial frame throughout. The result is a real, measurable age difference that has been confirmed with atomic clocks on aircraft and satellites.
Consider two twins, Alice (traveler) and Bob (stays on Earth). Alice boards a spacecraft and travels at constant velocity $$v$$ to a distant star, then returns at the same speed. From Bob's perspective on Earth:
From Alice's perspective, time dilation means her clocks run slower by the Lorentz factor:
$$\gamma = \frac{1}{\sqrt{1 - v^2/c^2}}$$
So Alice experiences only:
$$t_{\text{Alice}} = \frac{t_{\text{Earth}}}{\gamma} = t_{\text{Earth}}\sqrt{1 - \frac{v^2}{c^2}}$$
Additionally, Alice observes length contraction: the distance to the star appears shortened to $$d' = d/\gamma$$, which is consistent with her shorter travel time at velocity $$v$$.
Resolving the "paradox": One might ask: from Alice's frame, isn't Bob moving, so shouldn't Bob age less? The resolution is that the situation is not symmetric. Alice must undergo acceleration — at departure, at the turnaround point, and at arrival — changing reference frames. Bob remains inertial throughout. In general relativity terms, Alice follows a longer worldline through spacetime, and the principle of maximal aging states that the inertial (unaccelerated) path between two events accumulates the most proper time.
At $$v = 0.9c$$, $$\gamma \approx 2.294$$, so a 20-year Earth trip means Alice ages only ~8.7 years. At $$v = 0.99c$$, $$\gamma \approx 7.089$$, and the age difference becomes even more dramatic. At $$v = 0.9999c$$, Alice would age only ~100 days for every 20 Earth years.
The Traveler's Elapsed Time is how much the traveling twin actually ages during the journey — always less than the Earth time. The Age Difference shows how much younger the traveler is upon return. The Contracted Distance is the distance as measured by the traveler, shorter than the Earth-frame distance by the factor $$\gamma$$. As speed approaches $$c$$, the traveler's time approaches zero and the age difference approaches the full Earth time — in principle, one could travel to distant galaxies within a human lifetime at sufficient speed, though the energy requirements would be astronomical.
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At 90% of light speed, the traveler ages only ~8.7 years while the Earth twin ages 20 years — an 11.3-year age difference. The traveler sees the 9 light-year distance contracted to ~3.9 light-years.
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Results
At 99% of light speed over 50 Earth years, the traveler ages only ~7 years. They could reach a star 24.75 light-years away, but from their perspective, the distance is contracted to just ~3.5 light-years.
Yes. It has been confirmed experimentally multiple times. The Hafele-Keating experiment (1971) flew atomic clocks around the world on commercial jets and found they lost time compared to ground clocks, consistent with relativistic predictions. Muons created in the upper atmosphere live longer than stationary muons due to time dilation, allowing them to reach Earth's surface.
The key asymmetry is acceleration. The traveling twin must accelerate at departure, decelerate and reverse at the turnaround, and decelerate at arrival. These accelerations break the symmetry — the traveler changes inertial frames while the stay-at-home twin does not. In spacetime diagrams, the traveler's worldline has a kink at the turnaround, while the stay-at-home twin's worldline is straight (inertial).
The Lorentz factor $$\gamma = 1/\sqrt{1 - v^2/c^2}$$ quantifies relativistic effects. At low speeds, $$\gamma \approx 1$$ and there is no noticeable time dilation. At $$v = 0.5c$$, $$\gamma = 1.155$$. At $$v = 0.9c$$, $$\gamma = 2.294$$. At $$v = 0.99c$$, $$\gamma = 7.089$$. As $$v \to c$$, $$\gamma \to \infty$$.
In principle, yes. At $$v = 0.9999c$$ ($$\gamma \approx 70.7$$), a traveler could reach a star 100 light-years away in only ~1.4 years of their own time (though ~100 years would pass on Earth). The practical challenge is the immense energy required: accelerating even 1 kg to 0.9999c requires energy comparable to humanity's annual output.
Length contraction is the relativistic effect where distances along the direction of motion appear shortened by the factor $$\gamma$$: $$L' = L/\gamma$$. The traveling twin sees the distance to the destination star contracted, which is consistent with their shorter travel time. Both time dilation and length contraction are two aspects of the same Lorentz transformation.
Yes. During the turnaround acceleration, the traveling twin's plane of simultaneity sweeps forward in the Earth twin's time, accounting for the "missing" time. A full general-relativistic calculation (or equivalently, careful special-relativistic treatment with multiple frames) shows that both twins agree on the final age difference when they reunite. The paradox is a pedagogical puzzle, not a logical contradiction.
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