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  4. /Relativistic Momentum Calculator

Relativistic Momentum Calculator

Last updated: March 28, 2026

Calculator

Results

Lorentz Factor (γ)

1.342385

Relativistic Momentum (p)

2.684769e+8

kg·m/s

Classical Momentum (m₀v)

2.000000e+8

kg·m/s

Relativistic / Classical Ratio

1.3424

Momentum (p)

5.0236e+35

eV/c

Total Energy (E)

1.206475e+17

J

β = v/c

0.66712819

Results

Lorentz Factor (γ)

1.342385

Relativistic Momentum (p)

2.684769e+8

kg·m/s

Classical Momentum (m₀v)

2.000000e+8

kg·m/s

Relativistic / Classical Ratio

1.3424

Momentum (p)

5.0236e+35

eV/c

Total Energy (E)

1.206475e+17

J

β = v/c

0.66712819

The Relativistic Momentum Calculator computes the momentum of an object moving at relativistic speeds using $$p = \gamma m_0 v$$ and compares it with the classical Newtonian momentum $$p_{\text{classical}} = m_0 v$$. Relativistic momentum is a cornerstone of special relativity, essential for understanding particle collisions, cosmic ray interactions, and the operation of particle accelerators.

Unlike classical momentum, relativistic momentum increases without bound as velocity approaches c. The ratio of relativistic to classical momentum is simply the Lorentz factor γ, which means the correction is identical to time dilation: momentum is amplified by the same factor that stretches time. This calculator also provides the momentum in natural units (eV/c), standard in particle physics.

Visual Analysis

How It Works

The relativistic momentum of a particle with rest mass $$m_0$$ moving at velocity v is:

$$p = \gamma m_0 v = \frac{m_0 v}{\sqrt{1 - v^2/c^2}}$$

This definition ensures that conservation of momentum holds in all inertial reference frames, which the classical expression $$p = m_0 v$$ fails to do at high speeds. Key properties:

  • Reduces to classical at low speeds: When $$v \ll c$$, $$\gamma \approx 1$$ and $$p \approx m_0 v$$.
  • Diverges as v → c: Since $$\gamma \to \infty$$, the momentum becomes infinite — consistent with the impossibility of accelerating massive objects to c.
  • Conservation: In relativistic collisions, $$\sum \gamma_i m_{0i} \vec{v}_i$$ is conserved, not $$\sum m_{0i} \vec{v}_i$$.
  • Energy-momentum relation: $$E^2 = (pc)^2 + (m_0 c^2)^2$$. For massless particles (photons), $$E = pc$$.

The momentum connects to force through the relativistic form of Newton's second law: $$\vec{F} = \frac{d\vec{p}}{dt} = \frac{d}{dt}(\gamma m_0 \vec{v})$$. This is more complex than $$F = ma$$ because γ also depends on v and changes with time when force is applied.

In particle physics, momentum is commonly expressed in units of eV/c (electron volts divided by the speed of light). This comes from the energy-momentum relation and the convention of setting natural units. A 1 GeV/c proton has momentum of about $$5.34 \times 10^{-19}$$ kg·m/s.

For ultra-relativistic particles ($$v \approx c$$, $$\gamma \gg 1$$), the momentum is approximately $$p \approx E/c$$, and the distinction between rest energy and kinetic energy becomes negligible compared to the total energy.

Understanding Your Results

The relativistic/classical ratio equals the Lorentz factor γ, showing how much classical physics underestimates the momentum. A ratio of 2 means the true momentum is double the Newtonian prediction. In particle detector design, using classical momentum would give completely wrong predictions for particle trajectories in magnetic fields. The eV/c output is standard for comparing with particle physics data and accelerator specifications.

Worked Examples

Proton at 0.99c (Cosmic Ray)

Inputs

rest mass1.6726e-27
v fraction0.99
input modefraction_c

Results

gamma7.0888
p relativistic3.518e-18
p classical4.964e-19
ratio7.0888
p eV6583000000
total energy1.065e-9
beta0.99

A proton at 0.99c has 7× more momentum than classical physics predicts. Its momentum of ~6.6 GeV/c is in the range of cosmic ray protons commonly detected at Earth's surface.

1 kg Mass at 60% of Light Speed

Inputs

rest mass1
v fraction0.6
input modefraction_c

Results

gamma1.25
p relativistic224840000
p classical179880000
ratio1.25
p eV4.207e+35
total energy112350000000000000
beta0.6

A 1 kg mass at 0.6c has 25% more momentum than Newtonian prediction. The relativistic correction is already substantial at this speed.

Frequently Asked Questions

Relativistic momentum is $$p = \gamma m_0 v = \frac{m_0 v}{\sqrt{1 - v^2/c^2}}$$. This replaces the classical $$p = mv$$ and ensures momentum conservation holds in all inertial frames. The factor γ makes the momentum diverge as $$v \to c$$.

Classical momentum $$p = m_0v$$ is not conserved in relativistic collisions when analyzed from different reference frames. The relativistic definition $$p = \gamma m_0 v$$ restores conservation of momentum as a universal law. Without it, physics would give different predictions in different frames, violating the principle of relativity.

The relativistic energy-momentum relation is $$E^2 = (pc)^2 + (m_0c^2)^2$$. This fundamental equation connects total energy, momentum, and rest mass. For massless particles: $$E = pc$$. For particles at rest: $$E = m_0c^2$$. It is Lorentz-invariant — the same in all frames.

In particle physics, momentum is measured in eV/c (or GeV/c, TeV/c). This comes from the energy-momentum relation: since energy is in eV and $$E = pc$$ for ultra-relativistic particles, momentum has units of eV/c. A proton at rest has momentum 0 and rest energy 938.3 MeV, so momenta are often on the GeV/c scale.

The de Broglie relation $$\lambda = h/p$$ connects momentum to wavelength for matter waves. Using relativistic momentum gives the correct wavelength at all speeds. Higher momentum means shorter wavelength — this is why particle accelerators can probe smaller structures by increasing particle energy and momentum.

Photons have zero rest mass but nonzero momentum: $$p = E/c = h\nu/c = h/\lambda$$. The formula $$p = \gamma m_0 v$$ does not apply to photons (0 × ∞ is indeterminate). Instead, photon momentum comes directly from the energy-momentum relation $$E = pc$$.

Sources & Methodology

Einstein, A. (1905). On the Electrodynamics of Moving Bodies. Annalen der Physik. Jackson, J.D. (1998). Classical Electrodynamics, 3rd Ed. Wiley. Griffiths, D.J. (2020). Introduction to Elementary Particles, 2nd Ed. Wiley-VCH.
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