1.3423847
0.6671281904
200,000,000
m/s
0.4450600224
0.74494294
0.3423847
0.74494294
34.2385
%
25.5057
%
1.3423847
0.6671281904
200,000,000
m/s
0.4450600224
0.74494294
0.3423847
0.74494294
34.2385
%
25.5057
%
The Lorentz Factor Calculator computes the central quantity of special relativity — the Lorentz factor $$\gamma = \frac{1}{\sqrt{1 - \beta^2}} = \frac{1}{\sqrt{1 - v^2/c^2}}$$ along with all the derived relativistic effects: time dilation percentage, length contraction percentage, and the kinetic energy factor. The Lorentz factor γ appears in virtually every equation of special relativity and determines the magnitude of all relativistic effects.
At rest (v = 0), γ = 1 and there are no relativistic effects. As velocity increases toward c, γ grows from 1 toward infinity, and relativistic effects become increasingly pronounced. This calculator provides a comprehensive overview of how γ and its related quantities vary with velocity, making it an essential reference tool for physics students and researchers.
The Lorentz factor is defined as:
$$\gamma = \frac{1}{\sqrt{1 - \beta^2}}$$
where $$\beta = v/c$$ is the velocity expressed as a fraction of the speed of light. The Lorentz factor appears throughout special relativity:
Behavior of γ at notable velocities:
| β (v/c) | γ | Time Dilation | Length Contraction |
|---|---|---|---|
| 0.001 | 1.0000005 | ~0.00005% | ~0.00005% |
| 0.1 | 1.00504 | 0.5% | 0.5% |
| 0.5 | 1.1547 | 15.5% | 13.4% |
| 0.866 | 2.0 | 100% | 50% |
| 0.9 | 2.294 | 129% | 56.4% |
| 0.99 | 7.089 | 609% | 85.9% |
| 0.999 | 22.37 | 2137% | 95.5% |
| 0.9999 | 70.71 | 6971% | 98.6% |
The γ − 1 value is particularly useful because it directly gives the kinetic energy as a multiple of rest energy: $$KE = (\gamma - 1) m_0 c^2$$. When γ − 1 = 1, the kinetic energy equals the rest energy. For ultra-relativistic particles (γ ≫ 1), almost all the energy is kinetic.
For very small velocities, computing γ directly from $$1/\sqrt{1-\beta^2}$$ can suffer from floating-point precision loss. In such cases, the Taylor expansion $$\gamma \approx 1 + \beta^2/2 + 3\beta^4/8$$ gives better numerical precision.
The Lorentz factor γ is the master parameter of special relativity. γ = 1 means no relativistic effects; γ = 2 means time runs at half speed and lengths are halved; γ = 10 means time runs at 1/10 speed and lengths shrink to 10% of their rest values. The time dilation percentage shows how much extra time a stationary observer measures (e.g., 100% means double the proper time). The length contraction percentage shows how much shorter a moving object appears (e.g., 50% means half the rest length).
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At ISS orbital velocity (7.66 km/s), γ exceeds 1 by only 3.3 × 10⁻¹⁰ — astronauts age about 0.01 seconds less per year than people on Earth (ignoring gravitational effects).
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At γ = 1000, time dilates by a factor of 1000 — one second of proper time corresponds to ~17 minutes for a stationary observer. Length contracts to 0.1% of rest length.
The Lorentz factor $$\gamma = 1/\sqrt{1 - v^2/c^2}$$ is a dimensionless quantity that appears in all equations of special relativity. It ranges from 1 (at rest) to infinity (at the speed of light) and determines the magnitude of time dilation, length contraction, and the relationship between energy and momentum.
Beta $$\beta = v/c$$ is the velocity expressed as a fraction of the speed of light. It ranges from 0 (at rest) to 1 (at light speed, for massless particles). Using β simplifies many relativistic formulas and makes it easy to compare velocities to c. The Lorentz factor is $$\gamma = (1 - \beta^2)^{-1/2}$$.
Setting $$\gamma = 2$$ and solving: $$2 = 1/\sqrt{1-\beta^2}$$ gives $$\beta = \sqrt{3}/2 \approx 0.866$$. At about 86.6% of the speed of light, time runs at half speed, lengths contract by half, and momentum is double the classical value.
Time dilation: $$t = \gamma t_0$$ (multiply proper time by γ). Length contraction: $$L = L_0/\gamma$$ (divide proper length by γ). Time stretches by factor γ while length shrinks by factor 1/γ. Both effects have the same underlying cause: the geometry of Minkowski spacetime.
The quantity $$\gamma - 1$$ is the kinetic energy factor: $$KE = (\gamma - 1)m_0c^2$$. When $$\gamma - 1 = 1$$, the kinetic energy equals the rest energy. For a proton, this occurs at about 0.866c. The LHC achieves $$\gamma - 1 \approx 7000$$ for protons.
No. Since $$0 \leq \beta < 1$$ for massive particles, the term $$1 - \beta^2$$ is between 0 and 1, so its square root is also between 0 and 1, and the reciprocal $$\gamma$$ is always ≥ 1. A γ < 1 would require $$v > c$$, which is physically impossible for massive objects.
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