Punnett Square Calculators
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Monohybrid Cross (2×2 Punnett Square)
Cross Aa × Aa: gametes from each parent = A (½) and a (½). Grid (2×2):
A a A AA Aa a Aa aa
Genotype ratio: 1 AA : 2 Aa : 1 aa = 1:2:1. Phenotype ratio (complete dominance): 3 dominant : 1 recessive = 3:1. Probabilities: AA = 25%; Aa = 50%; aa = 25%.
Dihybrid Cross (4×4 Punnett Square)
Cross AaBb × AaBb: gametes = AB, Ab, aB, ab (each ¼). 4×4 = 16 cells. Phenotype ratio: 9 A_B_ : 3 A_bb : 3 aaB_ : 1 aabb = 9:3:3:1.
Probability Rule
Punnett square outcomes can also be calculated with the product rule: P(AA from Aa×Aa) = P(A from father) × P(A from mother) = ½ × ½ = ¼. P(aabb from AaBb × AaBb) = P(aa) × P(bb) = ¼ × ¼ = 1/16. For independent genes, probabilities multiply.
Testcross
Cross of unknown genotype × homozygous recessive (aa): if offspring are all dominant = unknown is AA; if half dominant, half recessive = unknown is Aa. Testcross is the standard genetic technique to determine unknown genotype.
Glossary
Frequently Asked Questions
Step 1: Identify the cross and determine parental gametes. For Aa parent: gametes are A and a (each with probability 1/2). Step 2: Write one parent's gametes across the top (columns) and the other parent's gametes down the side (rows). Step 3: Fill each cell by combining the row gamete letter with the column gamete letter. Step 4: Count genotype and phenotype combinations in the filled grid. Example: Aa × Aa → 4 cells: AA (col A × row A), Aa (col a × row A), Aa (col A × row a), aa (col a × row a) → genotype ratio 1:2:1 → phenotype ratio 3:1 (assuming complete dominance).
Count occurrences of each genotype in the filled cells. For Aa × Aa (4-cell grid): AA appears 1 time; Aa appears 2 times; aa appears 1 time → genotype ratio = 1:2:1 = 25%:50%:25%. Phenotype ratio (complete dominance): AA and Aa both show dominant phenotype = 3 cells; aa shows recessive = 1 cell → 3:1. For a dihybrid (16-cell grid): A_B_ appears in 9 cells; A_bb in 3; aaB_ in 3; aabb in 1 → 9:3:3:1. Remember: the Punnett square assumes all gametes have equal probability and all fertilizations are equally likely — true only with independent assortment and equal fitness.
A testcross crosses an organism of unknown genotype with a homozygous recessive (aa). Punnett squares for each possibility: If unknown = AA: AA × aa → all Aa offspring → all dominant phenotype (100% dominant). If unknown = Aa: Aa × aa → Aa (dominant) and aa (recessive) in 1:1 ratio → 50% dominant, 50% recessive. Interpretation: observe offspring phenotypes. If all are dominant → unknown was AA (homozygous). If half are dominant and half recessive → unknown was Aa (heterozygous). The testcross is the definitive method for determining whether a dominant phenotype individual is AA or Aa — it directly reveals what gametes the unknown parent can produce.
Punnett squares assume: independent assortment of alleles (valid only for genes on different chromosomes or far apart on the same chromosome). Equal probability of all gametes. Equal fitness of all genotypes (no selection). Random mating. Limitations: Punnett squares cannot handle: linked genes (genes on the same chromosome with recombination); polygenic traits (many genes contributing small effects); incomplete penetrance (not all genotype carriers show the phenotype); variable expressivity. For complex cases involving many genes or non-Mendelian inheritance, mathematical probability calculations or population genetics models replace the Punnett square. Despite limitations, Punnett squares remain the standard teaching and clinical tool for single-gene inheritance analysis.