Molal Concentration Calculators
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Molality Formula
m = moles of solute / kg of solvent
Units: mol/kg = molal (m). Note: the denominator is kg of SOLVENT, not kg of solution.
Example: dissolve 4.50 g of glucose (MW = 180.16 g/mol) in 500 g water: moles = 4.50/180.16 = 0.02498 mol. Molality = 0.02498 mol / 0.500 kg = 0.0499 m ≈ 0.050 m.
Molality vs. Molarity
For dilute aqueous solutions: m ≈ M (since 1 L water ≈ 1 kg). They diverge for concentrated solutions or non-aqueous solvents. Molality: independent of temperature and pressure; used for colligative properties. Molarity: depends on solution volume (changes with T); used for reaction stoichiometry and solution preparation.
Colligative Property Calculations Using Molality
Boiling point elevation: ΔTb = i × Kb × m. (water Kb = 0.512°C/m). Freezing point depression: ΔTf = i × Kf × m. (water Kf = 1.86°C/m). i = van't Hoff factor. Example: 0.100 m NaCl (i = 2) in water: ΔTf = 2 × 1.86 × 0.100 = 0.372°C → freezes at −0.372°C.
Molality from Density and Molarity
m = (M × 1000) / (density_solution_g/mL × 1000 − M × MW_solute). Useful for converting between concentration units when density and MW are known.
Glossary
Frequently Asked Questions
Molality (m) = moles of solute / kg of solvent. Molarity (M) = moles of solute / liter of solution. Key differences: Denominator: molality uses mass of solvent (kg); molarity uses volume of solution (L). Temperature dependence: molality is temperature-independent (mass doesn't change with T); molarity depends on temperature (volume changes). Practical impact: for aqueous solutions at room temperature and low concentrations, m ≈ M (since 1 L water ≈ 1 kg). They diverge significantly for: concentrated solutions; non-aqueous solvents; experiments over a range of temperatures. Use molarity for: lab preparations, stoichiometry. Use molality for: colligative properties (boiling point elevation, freezing point depression).
m = moles of solute / kg of solvent. Steps: (1) Calculate moles of solute = mass(g) / molar mass(g/mol). (2) Convert solvent mass to kg. (3) Divide. Example: dissolve 7.45 g of KCl (MW = 74.55 g/mol) in 200 g water: moles KCl = 7.45/74.55 = 0.0999 mol. kg water = 200/1000 = 0.200 kg. m = 0.0999/0.200 = 0.500 m. Critical: use mass of SOLVENT, not total mass of solution. If 7.45 g KCl + 200 g water = 207.45 g solution — molality uses 200 g (water only), not 207.45 g.
Colligative properties depend only on the concentration of solute particles — and must be measured at conditions (different temperatures, different boiling points) where using molarity would be inconsistent. Boiling point elevation: ΔTb = i × Kb × m. We measure the boiling point at 100°C + ΔTb; the solution volume is different at this elevated temperature — if we used molarity (which is volume-based), we'd need to recalculate the molarity at the new temperature. With molality (mass-based), the concentration is the same at all temperatures. Freezing point depression: similar argument — we measure at the depressed freezing point. Using m ensures the concentration is consistent regardless of the temperature at which the property is measured.
Osmolality measures the total solute particle concentration in a solution in terms of solute particles per kg of solvent — units are mOsm/kg or Osm/kg (osmolal). Osmolality ≈ molality × i (van't Hoff factor). For NaCl: i = 2 (dissociates to Na⁺ and Cl⁻); 0.154 m NaCl → osmolality ≈ 0.154 × 2 = 0.308 Osm/kg = 308 mOsm/kg (physiological ≈ 290 mOsm/kg). Osmolality of body fluids: blood plasma = 275–295 mOsm/kg; urine: 50–1,400 mOsm/kg (highly variable). Measured by osmometer (freezing point depression: ΔTf = 1.86 × osmolality). Clinical use: hyperosmolar = >295 mOsm/kg (dehydration, hypernatremia); hypoosmolar = <275 mOsm/kg (overhydration, SIADH).