Equivalent Weight Calculators
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What Is Equivalent Weight?
Equivalent weight (Eq. wt.) is calculated differently depending on the reaction type:
Acids
Eq. wt. = Molar mass / Number of ionizable H⁺ ions (n)
- HCl: n = 1 → Eq. wt. = 36.5/1 = 36.5 g/eq
- H₂SO₄: n = 2 → Eq. wt. = 98/2 = 49 g/eq
- H₃PO₄: n = 3 (if all 3 H⁺ are donated) → Eq. wt. = 98/3 = 32.7 g/eq
Bases
Eq. wt. = Molar mass / Number of OH⁻ provided (or H⁺ accepted)
- NaOH: Eq. wt. = 40/1 = 40 g/eq
- Ca(OH)₂: Eq. wt. = 74/2 = 37 g/eq
Salts
Eq. wt. = Molar mass / (Valence of cation × number of cations)
Na₂SO₄: cation Na⁺ (valence 1), 2 Na⁺ → Eq. wt. = 142/2 = 71 g/eq
Redox Reactions
Eq. wt. = Molar mass / Number of electrons transferred
KMnO₄ in acidic solution (Mn⁷⁺ → Mn²⁺, 5e⁻ change): Eq. wt. = 158/5 = 31.6 g/eq
Normality (N)
Normality = equivalents of solute per liter of solution:
N = number of equivalents / volume (L) = molarity × n
A 1 M H₂SO₄ solution is 2 N (2 equivalents/L). 1 N H₂SO₄ exactly neutralizes 1 N NaOH — regardless of their molarities.
Application in Titrations
At the equivalence point: N₁V₁ = N₂V₂
This simplification allows acid-base titrations to be calculated without tracking the number of protons per molecule — one equivalent of acid always neutralizes one equivalent of base.
Glossary
Frequently Asked Questions
Equivalent weight = Molar mass / number of reactive units (n). For acids, n = number of ionizable H⁺ ions. For bases, n = number of OH⁻ ions. For redox compounds, n = number of electrons transferred. Examples: HCl Eq. wt. = 36.5/1 = 36.5 g/eq; H₂SO₄ Eq. wt. = 98/2 = 49 g/eq; NaOH Eq. wt. = 40/1 = 40 g/eq.
Normality (N) = number of equivalents of solute per liter: N = Molarity × n, where n = equivalents per mole. A 1 M H₂SO₄ solution is 2 N because each H₂SO₄ provides 2 H⁺ (2 equivalents/mol). Normality is used in titration calculations because N₁V₁ = N₂V₂ at the equivalence point — one equivalent of acid always reacts with exactly one equivalent of base.
Equivalent weight simplifies titration calculations because all acids and bases react in a 1:1 equivalent ratio at the equivalence point — regardless of how many protons they donate. Rather than tracking that H₂SO₄ donates 2 H⁺ (so a 1 M H₂SO₄ reacts with 2 mol NaOH), normality automatically captures this: 1 N H₂SO₄ exactly neutralizes 1 N NaOH at the equivalence point by N₁V₁ = N₂V₂.
In acidic solution, KMnO₄ is reduced from Mn⁷⁺ to Mn²⁺ — a change of 5 electrons per manganese. Equivalent weight = Molar mass / electrons transferred = 158.03 / 5 = 31.6 g/eq. In neutral solution (MnO₄⁻ → MnO₂, Mn⁷⁺ → Mn⁴⁺, 3 electrons): Eq. wt. = 158/3 = 52.7 g/eq. The equivalent weight changes with reaction conditions.