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  3. /Motor & Transformer Calculators
  4. /Transformer Calculator

Transformer Calculator

Calculator

Results

Turns Ratio (N1/N2)

27.5

Primary Full-Load Current

5.25

A

Secondary Full-Load Current

144.34

A

Output Power at Unity PF

98

kW

Results

Turns Ratio (N1/N2)

27.5

Primary Full-Load Current

5.25

A

Secondary Full-Load Current

144.34

A

Output Power at Unity PF

98

kW

The Transformer Calculator computes key operating parameters of a three-phase power transformer including turns ratio, primary and secondary full-load currents, and output power. Transformers are the workhorses of the electrical power system, enabling efficient long-distance transmission at high voltage and safe distribution at utilization voltages.

The fundamental transformer equation is V1/V2 = N1/N2, where V represents voltages and N represents the number of turns on each winding. A step-down transformer with a 11,000V primary and 400V secondary has a turns ratio of 27.5:1. The secondary voltage is determined purely by this ratio (in an ideal transformer), while current transforms inversely: I1/I2 = N2/N1.

The kVA rating defines the transformer's apparent power capacity. For three-phase transformers, the full-load line current is calculated as I = kVA × 1000 / (√3 × VL), using the √3 factor that relates line-to-line voltage to the per-phase voltage in balanced three-phase systems.

Transformer efficiency is very high — typically 97-99% for distribution transformers — because transformers have no moving parts. Losses consist of core losses (eddy currents and hysteresis, roughly constant with voltage) and copper losses (I²R in windings, varying with load squared). Modern amorphous core transformers achieve over 99.5% efficiency under loading conditions.

Understanding transformer ratings is essential for load planning. A 100 kVA transformer with unity power factor loads can supply 100 kW. With 0.85 power factor loads, it only supplies 85 kW of real power while the transformer is fully loaded. The kVA rating constrains apparent power, not real power — hence the importance of power factor correction at transformer level.

Visual Analysis

How It Works

Turns ratio: a = V1/V2 (ideal). Three-phase full-load current: I = S/(√3 × VL) where S = kVA × 1000 VA. This applies separately to primary (use V1) and secondary (use V2). Output kW = kVA × η, valid for unity power factor loads. For other PF loads, output kW = kVA × PF × η.

Understanding Your Results

Primary current is always lower than secondary current for a step-down transformer (high voltage, low current on primary; low voltage, high current on secondary). Verify that upstream fusing and cabling is rated for primary current. Secondary busbars and switchgear must handle secondary current continuously.

Worked Examples

11kV/400V Distribution Transformer

Inputs

v111000
v2400
kva rating500
efficiency pct98.5

Results

turns ratio27.5
primary current26.24
secondary current721.69
output kw492.5

Standard UK distribution transformer. Secondary current of 722A requires large busbars. Primary needs 27.5A rated fusing.

Small Single-Phase Isolation Transformer (approx.)

Inputs

v1480
v2240
kva rating10
efficiency pct97

Results

turns ratio2
primary current12.03
secondary current24.06
output kw9.7

Note: calculator uses 3-phase formula; for single-phase, I = kVA×1000/V. Result shown is approximate for illustration.

Frequently Asked Questions

kVA is apparent power (voltage × current), kW is real power (kVA × power factor). Transformers are rated in kVA because they are limited by current (which causes I²R heating) regardless of whether that current is in phase with voltage. A transformer does not 'know' the power factor of its load.

Transformer hum at 100-120 Hz (double supply frequency) is caused by magnetostriction — the core laminations physically expand and contract with each magnetic cycle. The 120 Hz hum is characteristic (2× 60 Hz). Loose laminations, resonant structures, and DC offset on the supply can increase audible noise.

Transformer impedance (Z%, typically 4-6%) limits fault current and determines voltage regulation. Higher impedance means lower fault current (better protection) but poorer voltage regulation under load. For parallel operation, transformers must have matching impedance to share load proportionally.

Yes, with conditions: same voltage ratio, same impedance percentage, same vector group (e.g., Dyn11), and same phase sequence. Mismatched transformers circulate reactive current between them even at no-load, causing overheating and inefficiency.

Vector group (e.g., Dyn11) describes the winding configuration and phase shift: D=Delta primary, y=star secondary, n=neutral available, 11=30° phase shift (clock position). Vector group affects: neutral availability, harmonic handling, and parallel operation compatibility.

Overloading beyond kVA rating, high ambient temperature, blocked cooling vents, aging oil (in oil-cooled units), harmonic-rich loads (increase losses beyond nameplate), and load unbalance (increases neutral current and losses). Modern transformers have thermal protection relays and winding temperature indicators.

Sources & Methodology

IEEE C57.12 (Transformer Standards), IEC 60076, Blume L.F. 'Transformer Engineering', ABB Transformer Handbook
R

Roboculator Team

The Roboculator Team explains calculations, planning tools, and practical formulas in clear language for real-life situations.

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