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Spherical Coordinates Calculator

Last updated: March 15, 2026

Calculator

Results

Enter values to see results

ρ (distance from origin)

—

θ azimuthal (degrees)

—

°

φ polar (degrees)

—

°

θ (radians)

—

rad

φ (radians)

—

rad

x

—

y

—

z

—

Results

Enter values to see results

ρ (distance from origin)

—

θ azimuthal (degrees)

—

°

φ polar (degrees)

—

°

θ (radians)

—

rad

φ (radians)

—

rad

x

—

y

—

z

—

The Spherical Coordinates Calculator converts between Cartesian coordinates $$(x, y, z)$$ and spherical coordinates $$(\rho, \theta, \varphi)$$. Spherical coordinates describe a point in 3D space by its distance from the origin, an azimuthal angle in the $$xy$$-plane, and a polar angle from the positive $$z$$-axis. They are the natural coordinate system for problems with radial symmetry about a point, such as gravitational fields, electromagnetic radiation, and quantum mechanics.

The conversion from Cartesian to spherical (physics convention) is:

$$\rho = \sqrt{x^2 + y^2 + z^2}$$

$$\theta = \text{atan2}(y, x) \quad \text{(azimuthal angle, } 0° \text{ to } 360°\text{)}$$

$$\varphi = \arccos\left(\frac{z}{\rho}\right) \quad \text{(polar angle, } 0° \text{ to } 180°\text{)}$$

The conversion from spherical to Cartesian is:

$$x = \rho \sin\varphi \cos\theta$$

$$y = \rho \sin\varphi \sin\theta$$

$$z = \rho \cos\varphi$$

This calculator uses the physics convention (ISO standard) where $$\theta$$ is the azimuthal angle and $$\varphi$$ is the polar (zenith) angle. The mathematics convention swaps these two symbols.

The volume element in spherical coordinates is:

$$dV = \rho^2 \sin\varphi \, d\rho \, d\theta \, d\varphi$$

The Jacobian factor $$\rho^2 \sin\varphi$$ reflects how coordinate cells grow with distance from the origin and thin out near the poles.

Spherical coordinates are indispensable in physics. The gravitational potential of a point mass $$M$$ is $$V = -GM/\rho$$, depending only on the radial distance. The Coulomb potential of a point charge follows the same form. The Schrodinger equation for the hydrogen atom, when separated in spherical coordinates, yields the familiar quantum numbers $$n$$, $$l$$, and $$m$$ corresponding to radial, polar, and azimuthal modes. The angular solutions are spherical harmonics $$Y_l^m(\theta, \varphi)$$, which also appear in multipole expansions, computer graphics (environment mapping), and geophysics (Earth's gravitational field).

In astronomy, celestial coordinates (right ascension and declination) are spherical coordinates centered on the observer. In geophysics, latitude and longitude are spherical coordinates on Earth's surface. In acoustics, sound radiation from a point source spreads spherically, with intensity falling as $$1/\rho^2$$. In computer graphics, environment maps and HDRI lighting use spherical parameterization.

The Laplacian in spherical coordinates is:

$$\nabla^2 f = \frac{1}{\rho^2}\frac{\partial}{\partial\rho}\left(\rho^2\frac{\partial f}{\partial\rho}\right) + \frac{1}{\rho^2\sin\varphi}\frac{\partial}{\partial\varphi}\left(\sin\varphi\frac{\partial f}{\partial\varphi}\right) + \frac{1}{\rho^2\sin^2\varphi}\frac{\partial^2 f}{\partial\theta^2}$$

How It Works

Select the conversion direction. For Cartesian to Spherical, enter $$(x, y, z)$$. The calculator computes $$\rho$$ (distance from origin), $$\theta$$ (azimuthal angle in the xy-plane), and $$\varphi$$ (polar angle from the z-axis) in both degrees and radians. For Spherical to Cartesian, enter $$(\rho, \theta, \varphi)$$ in degrees and receive $$(x, y, z)$$.

Understanding Your Results

The radial distance $$\rho \geq 0$$ measures how far the point is from the origin. The azimuthal angle $$\theta$$ sweeps around the z-axis in the xy-plane. The polar angle $$\varphi$$ ranges from 0° (positive z-axis) through 90° (xy-plane) to 180° (negative z-axis). Points on the z-axis have undefined $$\theta$$; the origin has undefined $$\theta$$ and $$\varphi$$.

Worked Examples

Cartesian to Spherical: (1, 1, 1)

Inputs

directionto_sph
x1
y1
z1
rho in1.732
theta deg45
phi deg54.74

Results

rho out1.7321
theta out45
phi out54.7356
theta rad0.7854
phi rad0.9553
x out1
y out1
z out1

The point (1,1,1) has ρ = √3 ≈ 1.732, θ = 45° (equal x and y), and φ = arccos(1/√3) ≈ 54.74° from the z-axis.

Spherical to Cartesian: (10, 0°, 90°)

Inputs

directionto_cart
x1
y1
z1
rho in10
theta deg0
phi deg90

Results

rho out10
theta out0
phi out90
theta rad0
phi rad1.5708
x out10
y out0
z out0

ρ = 10 at φ = 90° (in the xy-plane) and θ = 0° gives the point (10, 0, 0) on the positive x-axis.

Frequently Asked Questions

In the physics convention (ISO 31-11), $$\theta$$ is the azimuthal angle (in the xy-plane) and $$\varphi$$ is the polar angle (from the z-axis). The mathematics convention swaps them: $$\theta$$ is polar and $$\varphi$$ is azimuthal. This calculator uses the physics convention.

Latitude is related to the polar angle by $$\text{lat} = 90° - \varphi$$ (measured from the equator rather than the pole). Longitude corresponds directly to the azimuthal angle $$\theta$$. Both describe positions on a sphere.

The volume element $$dV = \rho^2 \sin\varphi \, d\rho \, d\theta \, d\varphi$$ comes from the Jacobian of the coordinate transformation. The $$\rho^2$$ factor means shells at larger radii enclose more volume. The $$\sin\varphi$$ factor reflects that angular cells near the poles ($$\varphi = 0°$$ or $$180°$$) are thinner than those at the equator.

Spherical harmonics $$Y_l^m(\theta, \varphi)$$ are orthogonal functions on the sphere that arise from separating the angular part of the Laplacian. They are the angular eigenfunctions of the hydrogen atom, and they form a complete basis for expanding any function on a sphere.

Use spherical coordinates for problems symmetric about a point (gravitational/electric fields of point sources, radiation patterns). Use cylindrical coordinates for problems symmetric about a line (pipes, solenoids, rotating shafts).

When $$\varphi = 0°$$, the point is on the positive z-axis regardless of $$\theta$$. When $$\varphi = 180°$$, it is on the negative z-axis. In both cases, $$\theta$$ is undefined since there is no unique azimuthal direction at the poles. This is analogous to longitude being undefined at Earth's poles.

Sources & Methodology

Arfken, G. Mathematical Methods for Physicists. Academic Press. Griffiths, D. Introduction to Electrodynamics. Cambridge University Press. Jackson, J.D. Classical Electrodynamics. Wiley.
R

Roboculator Team

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