9,810
N/m³
9.81
kN/m³
62.449
lb/ft³
9,810
Pa
9.81
kPa
9,810
N/m³
9.81
kN/m³
62.449
lb/ft³
9,810
Pa
9.81
kPa
The Specific Weight Calculator computes the specific weight (also called unit weight) of a fluid using the relationship: $$\gamma = \rho g$$ where $$\rho$$ is the fluid density in kg/m³ and g is the gravitational acceleration in m/s². Specific weight has units of N/m³ and represents the gravitational force per unit volume of fluid.
Specific weight is widely used in civil engineering, hydraulics, and geotechnical engineering for hydrostatic pressure calculations, retaining wall design, dam analysis, and buoyancy problems. Unlike density (which is a pure material property), specific weight depends on the local gravitational field strength, making it location-dependent.
Specific weight relates density to gravitational force per unit volume:
$$\gamma = \rho g$$
This quantity appears directly in the hydrostatic pressure equation:
$$P = \gamma h$$
where h is the depth below the free surface. This makes specific weight the natural quantity for calculating pressures in fluids at rest — each meter of depth adds a pressure equal to the specific weight.
Key relationships and properties:
In engineering practice, specific weight is often tabulated in kN/m³ or lb/ft³. The standard value for water is commonly taken as 9.81 kN/m³ (62.4 lb/ft³) for design calculations.
The calculator also computes the hydrostatic pressure at 1 meter depth, which numerically equals the specific weight in Pa. This provides a quick reference for pressure-depth calculations in hydraulic engineering.
The calculated specific weight tells you the weight force per unit volume of the fluid. For water at standard conditions, γ ≈ 9810 N/m³ (9.81 kN/m³). The hydrostatic pressure at 1 m depth numerically equals γ in pascals. For engineering calculations, multiply γ by any depth h to find the gauge pressure at that depth: $$P = \gamma h$$. This is the foundation of all hydrostatic analysis in civil and hydraulic engineering.
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Freshwater at 20°C has γ ≈ 9792 N/m³ (9.79 kN/m³ or 62.3 lb/ft³). Each meter of water depth adds about 9.79 kPa of hydrostatic pressure.
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Mercury has γ ≈ 132,906 N/m³ (132.9 kN/m³). A 760 mm mercury column produces ≈ 101,009 Pa ≈ 1 atm, which is why mercury barometers work.
Specific weight (γ) is the weight force per unit volume of a substance: $$\gamma = \rho g$$. It has units of N/m³ (or kN/m³, lb/ft³). Unlike density, which is mass per volume, specific weight accounts for gravitational acceleration and thus varies with location. Water's specific weight is approximately 9.81 kN/m³ at Earth's surface.
Density (ρ) is mass per unit volume (kg/m³) — a fundamental material property independent of gravity. Specific weight (γ = ρg) is weight per unit volume (N/m³) — it depends on the local gravitational field. On the Moon, a fluid has the same density as on Earth but only 1/6 the specific weight.
The hydrostatic pressure at depth h below a free surface is $$P = \gamma h$$. This simple relationship makes specific weight the most convenient quantity for hydraulic engineering. For water (γ ≈ 9.81 kN/m³), the pressure increases by about 9.81 kPa per meter of depth, reaching 1 atm at about 10.33 m.
At standard conditions (4°C, sea-level gravity), water's specific weight is approximately 9810 N/m³ or 9.81 kN/m³ (62.4 lb/ft³). At 20°C, it drops slightly to about 9790 N/m³ due to thermal expansion reducing the density. The value 9.81 kN/m³ is commonly used in engineering calculations.
Archimedes' principle states that the buoyant force equals the weight of displaced fluid: $$F_b = \gamma_{\text{fluid}} \times V_{\text{displaced}}$$. An object floats when its average specific weight is less than the fluid's specific weight, and sinks when greater. At neutral buoyancy, the two specific weights are equal.
Yes, because gravitational acceleration decreases with altitude. At sea level, g ≈ 9.81 m/s², but at 10,000 m altitude, g ≈ 9.78 m/s² — a 0.3% decrease. While small for most engineering purposes, this variation matters in precision measurements and geophysical calculations. Temperature and pressure changes at altitude also affect the fluid density.
Roboculator Team
The Roboculator Team explains calculations, planning tools, and practical formulas in clear language for real-life situations.
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