1
-2,744.1518
0
0
1,372.0759
-1,882,592.2558
-16,428.9107
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1
-2,744.1518
0
0
1,372.0759
-1,882,592.2558
-16,428.9107
—
The Quadratic Regression Calculator fits a second-degree polynomial $$y = ax^2 + bx + c$$ to five data points using the least squares method. Enter paired (x, y) values and a prediction point, and the calculator determines the best-fit parabola, coefficient of determination (R²), vertex coordinates, and predicted value.
Quadratic regression is appropriate when the relationship between variables follows a curved, parabolic pattern rather than a straight line. Common applications include projectile motion, profit optimization, dose-response curves in pharmacology, and modeling phenomena with a single maximum or minimum.
The least squares method minimizes the sum of squared residuals: $$\sum_{i=1}^{n}(y_i - ax_i^2 - bx_i - c)^2$$. Taking partial derivatives with respect to $$a$$, $$b$$, and $$c$$ and setting them to zero yields a system of three normal equations that can be expressed in matrix form and solved using Cramer's rule or matrix inversion.
The normal equations form a 3×3 linear system: $$\begin{pmatrix} \sum x_i^4 & \sum x_i^3 & \sum x_i^2 \\ \sum x_i^3 & \sum x_i^2 & \sum x_i \\ \sum x_i^2 & \sum x_i & n \end{pmatrix} \begin{pmatrix} a \\ b \\ c \end{pmatrix} = \begin{pmatrix} \sum x_i^2 y_i \\ \sum x_i y_i \\ \sum y_i \end{pmatrix}$$. The determinant of the coefficient matrix must be nonzero for a unique solution to exist.
The vertex of the fitted parabola is at $$x_v = -\frac{b}{2a}$$, $$y_v = a x_v^2 + b x_v + c$$. When $$a > 0$$, the parabola opens upward and the vertex is a minimum; when $$a < 0$$, it opens downward and the vertex is a maximum. The vertex has practical significance in optimization problems such as finding the price that maximizes revenue or the angle that maximizes projectile range.
The coefficient of determination $$R^2 = 1 - \frac{SS_{res}}{SS_{tot}}$$ measures goodness of fit. With three parameters fitted to five points, R² may be high simply due to flexibility. Adjusted R² accounts for the number of parameters: $$R^2_{adj} = 1 - \frac{(1 - R^2)(n - 1)}{n - p - 1}$$ where $$p$$ is the number of predictors. Always compare quadratic fit against linear and higher-order alternatives to select the most parsimonious model that adequately describes the data.
Computes sums: Σx, Σy, Σx², Σx³, Σx⁴, Σxy, Σx²y, Σy². Sets up 3×3 normal equation matrix and solves via Cramer's rule (determinant method) for coefficients a, b, c. R² = 1 - SS_res/SS_tot. Vertex at x = -b/(2a). Predicted y = ax² + bx + c.
Coefficient a determines curvature: a > 0 opens upward (U-shape), a < 0 opens downward (inverted U). Coefficient b shifts the parabola horizontally. Coefficient c is the y-intercept. R² near 1 indicates a strong quadratic fit. The vertex represents the minimum or maximum of the fitted curve, useful for optimization.
Inputs
Results
Perfect fit to y = x² + 0.5x + 1. R² = 1.0, vertex at (-0.25, 0.9375).
Inputs
Results
y = -x² + 6x. Vertex (maximum) at x = 3, y = 9. Opens downward.
Use quadratic regression when your data shows curvature that a straight line cannot capture. If residuals from linear regression show a systematic U-shaped or inverted-U pattern, a quadratic model is likely more appropriate.
The coefficient a determines the curvature. When a > 0, the parabola opens upward (convex, with a minimum). When a < 0, it opens downward (concave, with a maximum). Larger |a| means tighter curvature.
The vertex is the minimum point (a > 0) or maximum point (a < 0) of the parabola, located at x = -b/(2a). It is critical in optimization: finding the input that produces the optimal output.
With 3 parameters and 5 data points, there are only 2 degrees of freedom for residuals. R² can appear high due to model flexibility rather than a true quadratic relationship. Use adjusted R² and consider whether quadratic is theoretically justified.
Quadratic regression is polynomial regression of degree 2. Higher-degree polynomials (cubic, quartic) can fit more complex curves but risk overfitting. Quadratic is the simplest polynomial that captures a single bend in the data.
Cramer's rule solves the 3×3 system of normal equations by computing determinants. Each coefficient equals the ratio of a modified determinant (replacing one column with the right-hand side) to the main determinant. It provides an exact algebraic solution.
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