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  1. Home
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  4. /Multifactorial Calculator

Multifactorial Calculator

Last updated: March 28, 2026

Calculator

Results

Multifactorial Result

3,840

Regular n! (for comparison)

3,628,800

n! / multifactorial

945

Number of Terms Multiplied

5

First (largest) Term

10

Last (smallest) Term

2

ln(result)

8.253228

Results

Multifactorial Result

3,840

Regular n! (for comparison)

3,628,800

n! / multifactorial

945

Number of Terms Multiplied

5

First (largest) Term

10

Last (smallest) Term

2

ln(result)

8.253228

The Multifactorial Calculator computes generalized factorials where you skip by a step size $$k$$ instead of multiplying every consecutive integer. The double factorial ($$n!!$$) multiplies every other integer, the triple factorial ($$n!!!$$) multiplies every third integer, and so on.

The formal definition of the $$k$$-th multifactorial is:

$$n!^{(k)} = n \times (n-k) \times (n-2k) \times \cdots$$

where the product continues while terms remain positive. For the double factorial specifically:

$$n!! = \begin{cases} n \times (n-2) \times \cdots \times 2 & \text{if } n \text{ is even} \\ n \times (n-2) \times \cdots \times 1 & \text{if } n \text{ is odd} \end{cases}$$

Multifactorials appear in many areas of advanced mathematics and physics. The double factorial is essential in evaluating Gaussian integrals, computing Wallis-type products, and expressing the volume of hyperspheres. In combinatorics, $$(2n-1)!!$$ counts the number of ways to pair $$2n$$ objects (perfect matchings). The triple factorial appears in certain hypergeometric function identities and series expansions in quantum mechanics.

The calculator also shows the regular factorial $$n!$$ for comparison, letting you see how multifactorials relate to standard factorials through their ratio.

Visual Analysis

How It Works

The calculator multiplies all terms of the form $$n - jk$$ that are positive:

$$n!^{(k)} = \prod_{j=0}^{m-1} (n - jk) \quad \text{where } m = \lceil n/k \rceil$$

For k = 1 (standard factorial): $$10!^{(1)} = 10 \times 9 \times 8 \times \cdots \times 1 = 3628800$$

For k = 2 (double factorial): $$10!! = 10 \times 8 \times 6 \times 4 \times 2 = 3840$$

For k = 3 (triple factorial): $$10!!! = 10 \times 7 \times 4 \times 1 = 280$$

The implementation uses up to 15 terms (sufficient for $$n \leq 30$$), with terms that would go below 1 automatically replaced by 1 (multiplicative identity). The term count equals $$\lceil n/k \rceil$$.

Understanding Your Results

The ratio $$n!/n!^{(k)}$$ tells you how many additional factors the standard factorial includes. For $$k=2$$, the double factorial captures roughly the square root of the full factorial in logarithmic terms. A larger step $$k$$ means fewer terms multiplied, yielding a smaller result. The term count shows exactly how many integers participate in the product.

Worked Examples

Double factorial of 10

Inputs

n10
k2

Results

result3840
regular factorial3628800
ratio945
term count5
first term10
last term2

10!! = 10 × 8 × 6 × 4 × 2 = 3840. Compare to 10! = 3,628,800 — the ratio is 945 = 9!! (the odd double factorial).

Triple factorial of 12

Inputs

n12
k3

Results

result2160
regular factorial479001600
ratio221760
term count4
first term12
last term3

12!!! = 12 × 9 × 6 × 3 = 2160. Only 4 terms are multiplied with step size 3.

Frequently Asked Questions

The double factorial $$n!!$$ multiplies every other integer from $$n$$ down. For even $$n$$: $$8!! = 8 \times 6 \times 4 \times 2 = 384$$. For odd $$n$$: $$7!! = 7 \times 5 \times 3 \times 1 = 105$$. It is not the factorial of the factorial — that would be $$(n!)!$$, a much larger number.

Double factorials appear in the Wallis product for $$\pi$$, in the volume of n-dimensional spheres ($$V_n \propto \pi^{n/2}/\Gamma(n/2+1)$$), in Gaussian integrals ($$\int_0^\infty x^{2n}e^{-x^2}dx = \frac{(2n-1)!!\sqrt{\pi}}{2^{n+1}}$$), and in the expansion coefficients of Legendre polynomials.

For even $$n = 2m$$: $$n! = n!! \times (n-1)!!$$, meaning the full factorial splits into the product of even and odd double factorials. Also, $$(2m)!! = 2^m \cdot m!$$. For example, $$10!! = 2^5 \cdot 5! = 32 \times 120 = 3840$$.

Yes, via generalizations of the Gamma function. The double factorial extends to complex arguments through $$z!! = 2^{z/2} \pi^{(1-\cos(\pi z))/4} \cdot \Gamma(z/2 + 1) / \Gamma(1/2)^{(1-\cos(\pi z))/2}$$, though the standard integer definition is far more common in practice.

Multifactorials grow slower than regular factorials because they skip terms. The double factorial grows roughly as $$n!! \sim \sqrt{2}(n/2)^{n/2}e^{-n/2}$$, which is much slower than $$n! \sim \sqrt{2\pi n}(n/e)^n$$. The larger the step $$k$$, the slower the growth.

The ratio equals the product of all integers from 1 to $$n$$ that are not included in the multifactorial. For $$n!!/n!! = (n-1)!!$$ when $$n$$ is even. This ratio helps convert between multifactorial and standard factorial expressions in derivations.

Sources & Methodology

Arfken, G. B. & Weber, H. J. — Mathematical Methods for Physicists (7th ed., Academic Press, 2012); Dale, A. I. — Double factorials and their applications; OEIS — A006882 (double factorials), A007661 (triple factorials), https://oeis.org/
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