8.0000e-14
N
8.0000e-14
N
0.0000e+0
N
1.000000
1000000.0000
m/s
5.0000e+5
N/C
0.0000e+0
N/m
8.0000e-14
N
8.0000e-14
N
0.0000e+0
N
1.000000
1000000.0000
m/s
5.0000e+5
N/C
0.0000e+0
N/m
The Magnetic Force Calculator determines the force experienced by a charged particle moving through a magnetic field or by a current-carrying wire placed in a magnetic field. It uses the Lorentz force law $$F = qvB\sin\theta$$ for moving charges and $$F = BIL$$ for current-carrying conductors.
Magnetic forces are central to electric motors, particle accelerators, mass spectrometers, and countless electromagnetic devices. Unlike electric forces, magnetic forces act perpendicular to the velocity of charged particles, causing circular or helical motion rather than acceleration along the field direction.
The magnetic force on a moving charged particle is given by the Lorentz force law:
$$\vec{F} = q\vec{v} \times \vec{B}$$
The magnitude is $$F = qvB\sin\theta$$, where θ is the angle between the velocity vector and the magnetic field vector. Key features:
For a straight wire of length L carrying current I in a uniform field B:
$$F = BIL\sin\theta$$
When the wire is perpendicular to the field (θ = 90°), this simplifies to $$F = BIL$$. This is the principle behind electric motors, where current-carrying coils experience torque in a magnetic field.
The direction of force on a wire follows the same right-hand rule: point fingers from current direction toward B, and the thumb gives the force direction. For negative charges (electrons), the force direction reverses.
The calculated force tells you the magnitude of the magnetic force in newtons. For charged particles, this force causes circular motion with radius $$r = \frac{mv}{qB}$$. For wires in motors, the force produces torque. Note that if θ = 0° (particle moving parallel to the field), the force is zero — the magnetic field only deflects particles with a velocity component perpendicular to it.
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An electron at 5×10⁶ m/s in Earth's field (~50 μT) experiences ~4×10⁻¹⁷ N, causing it to spiral along field lines.
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Results
A 15 cm wire carrying 25 A in a 0.8 T motor field experiences 3 N of force — enough to produce useful mechanical torque.
The Lorentz force law gives the total electromagnetic force on a charged particle: $$\vec{F} = q(\vec{E} + \vec{v} \times \vec{B})$$. The magnetic component $$q\vec{v} \times \vec{B}$$ depends on the particle's velocity and is always perpendicular to it, while the electric component $$q\vec{E}$$ acts along the electric field regardless of velocity.
The magnetic force $$\vec{F} = q\vec{v} \times \vec{B}$$ is always perpendicular to the velocity. Since work is $$W = \vec{F} \cdot \vec{v}$$, and the dot product of perpendicular vectors is zero, the magnetic force does no work. It changes the direction of motion but not the kinetic energy.
When θ = 0° or 180°, sin(θ) = 0, so the magnetic force is zero. The particle continues in a straight line unaffected by the field. Only the component of velocity perpendicular to B contributes to the magnetic force.
Current in a wire is the flow of charges: I = nqvA, where n is charge density, A is cross-sectional area. For a wire of length L, the total force on all moving charges gives F = BIL. It is the macroscopic form of the Lorentz force applied to many charge carriers simultaneously.
For positive charges: point your fingers in the direction of velocity (v), curl them toward B, and your thumb points in the direction of force (F). For negative charges (electrons), the force is in the opposite direction. For wires, replace v with the current direction I.
In a motor, current-carrying coils sit in a magnetic field. The force F = BIL on each side of the coil creates a torque that spins the rotor. By switching current direction each half-turn (commutation), continuous rotation is maintained. The torque is proportional to B, I, and the coil area.
Roboculator Team
The Roboculator Team explains calculations, planning tools, and practical formulas in clear language for real-life situations.
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