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  1. Home
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  3. /Heat & Temperature Calculators
  4. /Latent Heat Calculator

Latent Heat Calculator

Last updated: March 17, 2026

Calculator

Results

Primary Result

334,000

Heat Energy

334,000

J

Heat Energy

334

kJ

Heat Energy

0.092778

kWh

Mass

1

kg

Latent Heat Used

334,000

J/kg

Specific Energy

0.092778

kWh/kg

Specific Energy

0.334

MJ/kg

Results

Primary Result

334,000

Heat Energy

334,000

J

Heat Energy

334

kJ

Heat Energy

0.092778

kWh

Mass

1

kg

Latent Heat Used

334,000

J/kg

Specific Energy

0.092778

kWh/kg

Specific Energy

0.334

MJ/kg

The Latent Heat Calculator computes the energy required for a substance to undergo a phase transition—melting, freezing, boiling, or condensation—without changing temperature, using the equation Q = mL. Unlike sensible heat (Q = mcΔT), latent heat is absorbed or released at a constant temperature as molecular bonds rearrange.

This tool covers common substances and phase transitions, from melting ice to boiling water to smelting metals. Understanding latent heat is essential for HVAC design, food science, metallurgy, and atmospheric physics where phase changes dominate energy budgets.

Visual Analysis

How It Works

The latent heat equation is:

$$Q = m \cdot L$$

where Q is the heat energy (J), m is the mass (kg), and L is the specific latent heat of the transition (J/kg). There are two main types:

$$L_f = \text{latent heat of fusion (solid} \leftrightarrow \text{liquid)}$$

$$L_v = \text{latent heat of vaporization (liquid} \leftrightarrow \text{gas)}$$

For water, Lf = 334,000 J/kg at 0 °C and Lv = 2,260,000 J/kg at 100 °C. Notice that vaporization requires roughly 6.8 times more energy than fusion—breaking intermolecular bonds completely to form a gas demands far more energy than merely loosening them to form a liquid.

This explains why steam burns are far more dangerous than boiling-water burns: condensing steam releases 2.26 MJ per kilogram onto your skin in addition to the heat of the hot water itself.

Understanding Your Results

The calculated Q represents the total energy exchanged during the phase change at constant temperature. This energy goes entirely into changing the molecular arrangement, not the kinetic energy (temperature) of the molecules.

For practical applications: to melt 1 kg of ice at 0 °C you need 334 kJ, but to then heat that water from 0 °C to 100 °C you need an additional 418.6 kJ (using Q = mcΔT), and to boil it requires yet another 2260 kJ. The vaporization step dominates the total energy budget.

Worked Examples

Melting Ice for a Cooler

Inputs

mass5
phasewater_fusion
latent heat334000
solve forQ

Results

heat joules1670000
heat kj1670
heat kwh0.4639
effective l334000
mass result0

Melting 5 kg of ice absorbs 1670 kJ from the cooler contents, keeping them cold.

Boiling Water in a Kettle

Inputs

mass1.5
phasewater_vaporization
latent heat2260000
solve forQ

Results

heat joules3390000
heat kj3390
heat kwh0.9417
effective l2260000
mass result0

Completely vaporizing 1.5 kg of water at 100 °C requires 3390 kJ—nearly 1 kWh of energy.

Frequently Asked Questions

Latent heat is the energy absorbed or released during a phase change at constant temperature. 'Latent' means hidden—the energy changes the state of matter without producing a measurable temperature change.

Vaporization completely separates molecules against all intermolecular forces to form a gas, while fusion only partially loosens the solid structure. The energy required to fully overcome molecular attraction is much greater.

Yes, slightly. For example, water's latent heat of vaporization decreases from 2,500 kJ/kg at 0 °C to 2,260 kJ/kg at 100 °C and reaches zero at the critical point (374 °C). The values in this calculator are at standard phase-change temperatures.

Combine both formulas: first Q₁ = mcΔT to heat to the phase-change temperature, then Q₂ = mL for the transition, then Q₃ = mcΔT again if heating continues. Total Q = Q₁ + Q₂ + Q₃.

Sublimation is the direct transition from solid to gas (like dry ice). Its latent heat equals the sum of fusion and vaporization: Lsub = Lf + Lv. For water ice, Lsub ≈ 2,830,000 J/kg.

Sweat evaporating from your skin absorbs latent heat of vaporization from your body. Each gram of sweat that evaporates removes about 2,260 J of heat, making evaporative cooling highly effective.

Sources & Methodology

Çengel, Y. A. & Boles, M. A. (2019). Thermodynamics: An Engineering Approach, 9th Edition. McGraw-Hill. Halliday, D., Resnick, R., & Walker, J. (2013). Fundamentals of Physics, 10th Edition. Wiley.
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Roboculator Team

The Roboculator Team explains calculations, planning tools, and practical formulas in clear language for real-life situations.

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