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  1. Home
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  4. /Graham's Law of Effusion Calculator

Graham's Law of Effusion Calculator

Calculator

Results

Effusion Rate Ratio (r1/r2)

4

Effusion Rate of Gas 1

4

mol/s

Time Ratio for Same Amount (t1/t2)

0.25

Time for Gas 1 to Effuse Reference Amount

0.25

s

Time for Gas 2 to Effuse Reference Amount

1

s

Molar Mass Ratio (M2/M1)

16

Results

Effusion Rate Ratio (r1/r2)

4

Effusion Rate of Gas 1

4

mol/s

Time Ratio for Same Amount (t1/t2)

0.25

Time for Gas 1 to Effuse Reference Amount

0.25

s

Time for Gas 2 to Effuse Reference Amount

1

s

Molar Mass Ratio (M2/M1)

16

Graham's Law of Effusion Calculator determines the relative rates at which two gases escape through a small opening (effusion) or spread through another gas (diffusion). Enter the molar masses of two gases to find their rate ratio. Lighter gases effuse faster than heavier ones, with the rate ratio being the square root of the inverse molar mass ratio.

Discovered by Thomas Graham in 1848, this law has practical applications in gas separation (including uranium isotope enrichment), leak detection, gas chromatography, and understanding atmospheric gas behavior. It is also used to estimate how quickly different gases escape from containers or spread in enclosed spaces.

Visual Analysis

How It Works

Graham's law of effusion states:

$$\frac{r_1}{r_2} = \sqrt{\frac{M_2}{M_1}}$$

where \(r_1\) and \(r_2\) are the effusion rates of gases 1 and 2, and \(M_1\) and \(M_2\) are their molar masses. The time ratio is the inverse of the rate ratio:

$$\frac{t_1}{t_2} = \frac{r_2}{r_1} = \sqrt{\frac{M_1}{M_2}}$$

This law is derived from the kinetic molecular theory. At the same temperature, all gases have the same average kinetic energy: \(\frac{1}{2}mv^2 = \frac{3}{2}k_BT\). Therefore, lighter molecules move faster:

$$v_{rms} = \sqrt{\frac{3RT}{M}}$$

Since effusion rate is proportional to molecular speed, the rate ratio equals the inverse square root of the molar mass ratio. This applies strictly to effusion (escape through a pinhole) but approximately to diffusion (spreading through another gas) as well.

Understanding Your Results

The rate ratio shows how many times faster Gas 1 effuses compared to Gas 2. If the ratio is greater than 1, Gas 1 is faster (lighter). The time ratio is the inverse: it shows how the time for effusion compares. For example, hydrogen (M=2) effuses 4 times faster than oxygen (M=32) because sqrt(32/2) = 4. This means hydrogen escapes from a container 4 times faster through any small opening.

Worked Examples

Hydrogen vs Oxygen Effusion

Inputs

M12
M232
rate21

Results

rate ratio4
rate14
time ratio0.25

Hydrogen (M=2 g/mol) effuses 4 times faster than oxygen (M=32 g/mol). This is why hydrogen balloons deflate much faster than helium balloons, and helium faster than air-filled ones.

UF₆ Isotope Separation (U-235 vs U-238)

Inputs

M1349
M2352
rate21

Results

rate ratio1.0043
rate11.0043
time ratio0.9957

The rate ratio for UF₆ with U-235 vs U-238 is only 1.0043 — a 0.43% difference. This tiny separation factor is why uranium enrichment requires thousands of successive diffusion stages (gaseous diffusion method).

Frequently Asked Questions

Effusion is the escape of gas molecules through a tiny hole (smaller than the mean free path) into a vacuum. Diffusion is the gradual mixing of gas molecules through another gas. Graham's law applies exactly to effusion and approximately to diffusion. Diffusion is slower because molecules collide with other gas molecules.

At the same temperature, all gas molecules have the same average kinetic energy (½mv²). Since lighter molecules have less mass, they must move faster to have the same kinetic energy. Faster molecules reach the hole more often, resulting in a higher effusion rate.

Natural uranium contains 0.7% U-235 and 99.3% U-238. In gaseous diffusion, UF₆ gas is passed through porous barriers. ²³⁵UF₆ (M=349) diffuses slightly faster than ²³⁸UF₆ (M=352) with a separation factor of ~1.0043. Thousands of cascaded stages gradually increase the U-235 concentration for nuclear fuel or weapons.

Graham's law compares two pure gases effusing independently. In a mixture, each gas effuses at a rate determined by its own molar mass and partial pressure. The law applies to each component separately, which is the basis for gas separation by effusion.

Helium (M=4 g/mol) effuses through the tiny pores in the balloon material about 2.7 times faster than nitrogen (M=28, the main component of air) because √(28/4) ≈ 2.65. This is why helium balloons lose buoyancy within hours to days, while air-filled balloons last weeks.

Higher temperature increases the average speed of all gas molecules (v_rms ∝ √T), so effusion rates increase with temperature. However, Graham's law gives the ratio of rates at the same temperature, and this ratio is independent of temperature — it depends only on the molar mass ratio.

The mean free path is the average distance a molecule travels between collisions. For true effusion, the hole must be smaller than the mean free path so molecules pass through individually without collisions. If the hole is larger, bulk flow occurs instead of effusion, and Graham's law no longer applies exactly.

Yes! By measuring the effusion rates of an unknown gas and a known gas under identical conditions: M_unknown = M_known × (r_known/r_unknown)². This was historically important for determining molar masses of gases before mass spectrometry.

Helium leak detection uses Graham's law: helium's small molar mass and size allow it to effuse through tiny leaks much faster than air. By pressurizing a system with helium and using a mass spectrometer to detect helium outside, even extremely small leaks can be found.

Graham's law is a direct consequence of the Maxwell speed distribution. The rate ratio equals the ratio of root-mean-square speeds: r₁/r₂ = v_rms1/v_rms2 = √(M₂/M₁). Since v_rms = √(3RT/M), lighter molecules always move faster at the same temperature.

Sources & Methodology

Graham, T., Philosophical Transactions of the Royal Society, 136, 573-631 (1846). Atkins, P. & de Paula, J., Atkins' Physical Chemistry, 11th Edition, Oxford University Press (2018). Zumdahl, S. & Zumdahl, S., Chemistry, 10th Edition, Cengage Learning (2018).
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