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  1. Home
  2. /Biology
  3. /Punnett Square Calculators
  4. /Dihybrid Cross Calculator

Dihybrid Cross Calculator

Last updated: February 24, 2026

Calculator

Results

A_B_ Phenotype

56.25

%

A_bb Phenotype

18.75

%

aaB_ Phenotype

18.75

%

aabb Phenotype

6.25

%

Gene A Dominant Phenotype

75

%

Gene B Dominant Phenotype

75

%

Expected 1 in N Double Recessive

16

Punnett Square Cells

16

Results

A_B_ Phenotype

56.25

%

A_bb Phenotype

18.75

%

aaB_ Phenotype

18.75

%

aabb Phenotype

6.25

%

Gene A Dominant Phenotype

75

%

Gene B Dominant Phenotype

75

%

Expected 1 in N Double Recessive

16

Punnett Square Cells

16

The Dihybrid Cross Calculator predicts offspring phenotype ratios when two genes are considered simultaneously. A dihybrid cross involves parents that are heterozygous for two independently assorting genes, producing the famous 9:3:3:1 phenotype ratio in the F2 generation first observed by Mendel.

Enter the genotype of each parent for both genes (number of dominant alleles: 2=homozygous dominant, 1=heterozygous, 0=homozygous recessive) to see the expected offspring phenotype classes.

Visual Analysis

How It Works

For two independently assorting genes, the probability of each phenotype class is the product of the individual gene probabilities. For the classic AaBb × AaBb cross:

Gene A alone: 3/4 dominant, 1/4 recessive. Gene B alone: 3/4 dominant, 1/4 recessive.

Both dominant (A_B_): 3/4 × 3/4 = 9/16

A dominant, B recessive (A_bb): 3/4 × 1/4 = 3/16

A recessive, B dominant (aaB_): 1/4 × 3/4 = 3/16

Both recessive (aabb): 1/4 × 1/4 = 1/16

Worked Examples

Classic F2 dihybrid (AaBb × AaBb)

Inputs

p1 gene11
p1 gene21
p2 gene11
p2 gene21

Results

pct ab56.25
pct ab rec18.75
pct rec b18.75
pct rec rec6.25
total combos16

The classic 9:3:3:1 ratio: 56.25% show both dominant traits, 18.75% each show one dominant and one recessive, and 6.25% show both recessive traits.

Dihybrid test cross (AaBb × aabb)

Inputs

p1 gene11
p1 gene21
p2 gene10
p2 gene20

Results

pct ab25
pct ab rec25
pct rec b25
pct rec rec25
total combos16

A test cross of AaBb × aabb produces four phenotype classes in equal proportions (1:1:1:1 or 25% each), confirming independent assortment.

Frequently Asked Questions

The 9:3:3:1 ratio describes the expected phenotype proportions in the F2 generation of a dihybrid cross between two heterozygous parents (AaBb × AaBb). Out of 16 equally likely outcomes: 9 show both dominant phenotypes, 3 show dominant A with recessive B, 3 show recessive A with dominant B, and 1 shows both recessive phenotypes.

Independent assortment is Mendel's second law, stating that genes on different chromosomes are inherited independently. During meiosis, the segregation of alleles at one locus does not influence the segregation at another locus (provided they are on different chromosomes). This is what produces the 9:3:3:1 ratio in dihybrid crosses.

Deviations occur with: linked genes (on the same chromosome), epistasis (one gene masks another), lethal allele combinations, incomplete dominance, or codominance. For linked genes, the recombinant classes are underrepresented. Epistasis can produce modified ratios like 9:7, 12:3:1, or 9:3:4.

Sources & Methodology

Griffiths, A.J.F. et al. Introduction to Genetic Analysis, 12th ed. Macmillan, 2020. Mendel, G. Experiments in Plant Hybridization, 1866.
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