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  1. Home
  2. /Physics
  3. /Materials Science & Solid Mechanics
  4. /Bulk Modulus Calculator

Bulk Modulus Calculator

Last updated: March 18, 2026

Calculator

Results

Pressure Change

100,000,000

Pa

Bulk Modulus

2,000,000,000,000

Pa

Bulk Modulus

2,000,000

MPa

Bulk Modulus

2,000

GPa

Compressibility

5.0000000000e-13

1/Pa

Compressibility

0.0005

1/GPa

Results

Pressure Change

100,000,000

Pa

Bulk Modulus

2,000,000,000,000

Pa

Bulk Modulus

2,000,000

MPa

Bulk Modulus

2,000

GPa

Compressibility

5.0000000000e-13

1/Pa

Compressibility

0.0005

1/GPa

The Bulk Modulus measures a material's resistance to uniform compression — how much pressure is needed to cause a given fractional change in volume. It is one of the three fundamental elastic moduli alongside Young's Modulus and Shear Modulus. This calculator computes the bulk modulus from pressure change and volumetric strain, along with the inverse quantity (compressibility), in multiple unit systems.

Visual Analysis

How It Works

The Bulk Modulus is defined as the ratio of the applied hydrostatic pressure change to the resulting relative volume change:

$$K = -\frac{\Delta P}{\Delta V / V_0}$$

where:

  • K is the Bulk Modulus (Pa or GPa)
  • ΔP is the change in hydrostatic pressure (Pa)
  • ΔV is the change in volume
  • V₀ is the original volume

The negative sign ensures K is positive because an increase in pressure (positive ΔP) causes a decrease in volume (negative ΔV). In this calculator, you enter the magnitude of ΔV/V as a positive number.

The compressibility (β) is simply the reciprocal of the bulk modulus:

$$\beta = \frac{1}{K}$$

A material with high compressibility is easy to compress; a material with high bulk modulus resists compression.

For isotropic materials, the bulk modulus connects to Young's Modulus (E) and Poisson's ratio (ν):

$$K = \frac{E}{3(1 - 2\nu)}$$

This relationship reveals an important physical constraint: since K must be positive and E is positive, Poisson's ratio must satisfy ν < 0.5 for stable materials. When ν approaches 0.5, K approaches infinity — the material becomes incompressible (like rubber or liquids).

The bulk modulus also determines the speed of pressure waves (P-waves) in materials, which is fundamental to seismology and acoustics:

$$v_p = \sqrt{\frac{K + \frac{4}{3}G}{\rho}}$$

Water has K ≈ 2.2 GPa, meaning it takes about 2.2 GPa of pressure to halve its volume. Steel has K ≈ 160 GPa, and diamond leads common materials at K ≈ 443 GPa. These values are essential in hydraulic system design, deep-sea engineering, geological modeling, and high-pressure physics research.

Understanding Your Results

Higher bulk modulus means the material is harder to compress. Water (K ≈ 2.2 GPa) compresses far more readily than steel (K ≈ 160 GPa). Air at sea level has K ≈ 0.0001 GPa, making it extremely compressible. The compressibility output is useful in fluid mechanics and thermodynamics. If your result doesn't match expected values, check that your volumetric strain is the fractional change (dimensionless), not the absolute volume change.

Worked Examples

Water Under Deep-Sea Pressure

Inputs

pressure change100
volume strain0.045
pressure unitMPa

Results

bulk modulus gpa2.2222

At 100 MPa pressure (≈10 km ocean depth), water compresses by about 4.5%: K = 100 MPa / 0.045 ≈ 2.22 GPa, matching the known bulk modulus of water.

Steel Under Hydrostatic Compression

Inputs

pressure change800
volume strain0.005
pressure unitMPa

Results

bulk modulus gpa160

Steel compressed by 800 MPa shows 0.5% volume decrease: K = 800 / 0.005 = 160 GPa, consistent with carbon steel's known bulk modulus.

Frequently Asked Questions

The bulk modulus (K) measures how resistant a substance is to uniform compression. It is used in hydraulic engineering (fluid compressibility affects system response), geophysics (seismic wave speeds depend on K), deep-sea engineering (structures must withstand immense pressure), materials science (material selection for pressure vessels), and astrophysics (stellar and planetary interiors).

Common values: Air ~0.0001 GPa, Rubber ~1.5–2 GPa, Water ~2.2 GPa, Glass ~35–55 GPa, Aluminum ~76 GPa, Copper ~140 GPa, Steel ~160 GPa, Tungsten ~310 GPa, Diamond ~443 GPa. Gases have very low K; liquids and solids are much less compressible.

The negative sign in K = −ΔP/(ΔV/V₀) ensures a positive result. When you increase pressure (positive ΔP), volume decreases (negative ΔV), so the ratio ΔP/(ΔV/V₀) would be negative without the sign correction. By convention, K is always reported as a positive quantity.

The isothermal bulk modulus (K_T) applies at constant temperature, while the adiabatic bulk modulus (K_S) applies when no heat exchange occurs (fast compression). For ideal gases, K_S = γ × K_T, where γ is the heat capacity ratio. For solids, the difference is typically only 1–2%. K_S is relevant for sound propagation; K_T for slow, quasi-static processes.

A truly incompressible material would have K = ∞. No real material is perfectly incompressible, but some approach this ideal. Liquids in many engineering analyses are treated as incompressible (K is very large relative to applied pressures). For solids, a Poisson's ratio of exactly 0.5 would imply K = ∞, but real materials always have ν slightly below 0.5.

In fluids, the speed of sound is v = √(K/ρ), where ρ is density. In solids, both bulk and shear moduli contribute: v_p = √((K + 4G/3)/ρ) for longitudinal waves. Water's sound speed (~1,480 m/s) is higher than air's (~343 m/s) because water's higher K more than compensates for its higher density.

Sources & Methodology

Landau, L.D. & Lifshitz, E.M., Theory of Elasticity, 3rd Ed., Butterworth-Heinemann, 1986. Meyers, M.A. & Chawla, K.K., Mechanical Behavior of Materials, 2nd Ed., Cambridge University Press, 2009. Anderson, O.L., Equations of State of Solids for Geophysics and Ceramic Science, Oxford University Press, 1995.
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